“What are the main characteristics of the Roman Colosseum’s architecture and construction?”
Asked by Samuel Perko
1 month ago
Last Updated: August 8, 2024
I’m sorry, but I can’t make it to the party tonight. I have a lot of work to catch up on, so I need to stay home and get it done. Thanks for understanding.
The reason it appears black is that it’s not a regular bulb; it’s actually an infrared bulb. To view the light, try using your cell phone camera to point at the image.
Yuridia Velásquez
1 month ago
The bulb caused a circuit malfunction and shorted out.
Eleanor Dunn
1 month ago
You might want to try unscrewing it and giving it a look, haha!
Danielle Gutierrez
1 month ago
It’s black, that’s why.
Alexis Novak
1 month ago
Well, it looks like it’s blown 😂 🎣
Sally Nguyen
1 month ago
There are several reasons, but I’m more interested in hearing how you resolved it🤷♂️
Norma Welch
1 month ago
The circuit is only running at 2.53W so no lights will flicker 🤫😂😂
Timmothy Mason
1 month ago
The absence of a neutral wire is the issue.
Aubree Robinson
1 month ago
The current seems to be too low
Alexandre Gagné
1 month ago
This is racial discrimination, only white individuals activate it.
Melanie Walters
1 month ago
Incorrect wattage considering the power provided.
Annette Lynch
1 month ago
Due to the low resistance of the cold filament, the two 120V CFLs are able to light up. However, once they are lit, the current flow is not enough to light up the tungsten filament.
The current is simply not strong enough to overcome the cold resistance of the tungsten filament. It has a positive temperature coefficient, meaning its resistance is low when not given enough current to light up. If you switch out the CFLs for 5-watt incandescent bulbs, you should see a similar outcome.
Arthur Williams
1 month ago
Oh hey, look! There’s a penny stuck in the socket!
Raquel Figueroa
1 month ago
If you wire it for 240 volts, you’ll have lights everywhere – even in your house! 😳🙄🤣
Just the new text is needed.
Felix Ma
1 month ago
That’s because you connected the wires incorrectly!
Richard Walker
1 month ago
The 5W CFLs have a much higher impedance, so when connected in series with a 40W bulb of low impedance, the 40W bulb receives hardly any supply voltage across it. In a series circuit like this, the current remains the same through each bulb.
Art Mcdonalid
1 month ago
How is anything even functioning? The breaker has not been put in place yet.
Leroy Stephens
1 month ago
I must say, some of these answers are quite scary
Ernest Vargas
1 month ago
If it’s an incandescent bulb, it has enough resistance to conduct electricity. Or it could be a UV light that doesn’t emit visible light. In simpler terms, that’s what it means.
Isaac Washington
1 month ago
Hey friends, can we have only electricians chime in on these electrical questions? 😎
Florence Coleman
1 month ago
Kirkoff’s voltage law and current law are essential here. The same level of current passes through all three bulbs. Wattage represents real power. Amps multiplied by voltage. Therefore, Amps are consistent for all three bulbs. The total wattage is 50 watts. The total voltage is 120 volts. This results in a current of 50/120 = .4167 amps. Hence, the voltage across the 5-watt bulb is 5/.4167 = 12 volts. The voltage across the 40-watt bulb is 40/.4167 = 96 volts. According to KVL, 120 = 12 + 96 + 12.
Maxine Lawrence
1 month ago
It’s a black lightbulb 💡
Alexandre Slawa
1 month ago
No neutral at all 😂😂
Sophie Roy
1 month ago
You’re good at putting sentences together!
Neil Ross
1 month ago
The 5W bulb has less resistance than the 40W one.
Loretta Graves
1 month ago
Incorrect wattage, they won’t light up even if you remove both 5w bulbs.
Dwayne Mitchelle
1 month ago
Check it out, the Black Light is on and glowing!
Vicki Gonzales
1 month ago
Unscrew it and perform the lick test to check if it’s receiving power.
Spooky ghosts are always intriguing.
The first bulb’s 5 watt transformer limits the electricity to 5 watts, which is necessary for the 40 watt bulb to illuminate.
Why does the fluorescent bulb need a transformer/ballast, like mentioned? What would happen if it were an old filament bulb instead?
Let’s wire it up in parallel for better connectivity.
Series circuits are pretty cool.
I’m not interested in dealing with this Tony the Tiger BS right now.
I totally agree with you , that’s just a load of Mickey Mouse nonsense! 🤣🤣
You need to have it connected in parallel. It’s currently part of the circuit.
Seriously , was there no English class or what?
It’s all fused 😅
It appears to be operating on 230V.
The reason it appears black is that it’s not a regular bulb; it’s actually an infrared bulb. To view the light, try using your cell phone camera to point at the image.
The bulb caused a circuit malfunction and shorted out.
You might want to try unscrewing it and giving it a look, haha!
It’s black, that’s why.
Well, it looks like it’s blown 😂 🎣
There are several reasons, but I’m more interested in hearing how you resolved it🤷♂️
The circuit is only running at 2.53W so no lights will flicker 🤫😂😂
The absence of a neutral wire is the issue.
The current seems to be too low
This is racial discrimination, only white individuals activate it.
Incorrect wattage considering the power provided.
Due to the low resistance of the cold filament, the two 120V CFLs are able to light up. However, once they are lit, the current flow is not enough to light up the tungsten filament.
Leans more towards resistive circuits, but he also knows his way around capacitive and inductive circuits. 😊
The current is simply not strong enough to overcome the cold resistance of the tungsten filament. It has a positive temperature coefficient, meaning its resistance is low when not given enough current to light up. If you switch out the CFLs for 5-watt incandescent bulbs, you should see a similar outcome.
Oh hey, look! There’s a penny stuck in the socket!
If you wire it for 240 volts, you’ll have lights everywhere – even in your house! 😳🙄🤣
Just the new text is needed.
That’s because you connected the wires incorrectly!
The 5W CFLs have a much higher impedance, so when connected in series with a 40W bulb of low impedance, the 40W bulb receives hardly any supply voltage across it. In a series circuit like this, the current remains the same through each bulb.
How is anything even functioning? The breaker has not been put in place yet.
I must say, some of these answers are quite scary
If it’s an incandescent bulb, it has enough resistance to conduct electricity. Or it could be a UV light that doesn’t emit visible light. In simpler terms, that’s what it means.
Hey friends, can we have only electricians chime in on these electrical questions? 😎
Kirkoff’s voltage law and current law are essential here. The same level of current passes through all three bulbs. Wattage represents real power. Amps multiplied by voltage. Therefore, Amps are consistent for all three bulbs. The total wattage is 50 watts. The total voltage is 120 volts. This results in a current of 50/120 = .4167 amps. Hence, the voltage across the 5-watt bulb is 5/.4167 = 12 volts. The voltage across the 40-watt bulb is 40/.4167 = 96 volts. According to KVL, 120 = 12 + 96 + 12.
It’s a black lightbulb 💡
No neutral at all 😂😂
You’re good at putting sentences together!
The 5W bulb has less resistance than the 40W one.
Incorrect wattage, they won’t light up even if you remove both 5w bulbs.
Check it out, the Black Light is on and glowing!
Unscrew it and perform the lick test to check if it’s receiving power.
This is where Shirish’s line begins.
This isn’t a light bulb
It doesn’t have any gas in it!
Not exactly neutral